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- Why is binary search log n?
- What is binary search with example?
- How do you find the number of iterations in binary search?
- Does binary search use two pointers?
Why is binary search log n?
To make a lookup more efficient, the tree must be balanced so that its maximum height is proportional to log(n) . In such case, the time complexity of lookup is O(log(n)) because finding any leaf is bounded by log(n) operations. But again, not every Binary Search Tree is a Balanced Binary Search Tree.
What is binary search with example?
Binary Search is a searching algorithm for finding an element's position in a sorted array. In this approach, the element is always searched in the middle of a portion of an array. Binary search can be implemented only on a sorted list of items. If the elements are not sorted already, we need to sort them first.
How do you find the number of iterations in binary search?
Mathematically Maximum iteration possible (Assuming case of only integer type) is = ceil( log2 ( initial_r - initial_l ) ) base of log is 2 because every time we are diving our range in half by taking a mid and switching to one of the half.
Does binary search use two pointers?
We've introduced a Binary Search template using two pointers, start and end, without recursion. The template can easily be applied to solve the following interview questions: Find Position of Element in Sorted Array.
